Friday, October 17, 2008

MYP Algebra 2 - Ch10 - Writing 2

p.605 #80

Describe how the equation of a circle is related to the Pythagorean theorem.
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9 comments:

Anonymous said...

the Pythagorean theorem is a^2+b^2= c^2
which isthe same as the equation of a cirlce: a^2+b^2= c^2

8:56 PM
Anonymous said...

i mean x^2+y^2= r^2
with different variables

3:53 PM
Anonymous said...

The pythagorean theorem is a^2 + b^2 = c^2, while the equation for a circle is x^2 + y^2 = r^2. In both equations all three variables are squared and the sum of the squares of two values is equal to the square of another value. The forms of the equations are the same but the variables are different.

4:34 PM
Anonymous said...

The Pythagorean Theorem is a^2+b^b^2=c^2 and the equation of a circle is x^2+y^2=r^2. Both of them have all three variables squared and the sum of the first two terms squared in the equation is equal the third term squared.

6:46 PM
Anonymous said...

The pythagorean theorem and the equation of a circle are related in the fact that they have three vatiables all being raised to the second power.
The pythagorean theorem is
a^2+b^2=c^2 and the equation of a circle is x^2+y^2=r^2
These equations as you can see above, are also, similiar because the sum of the two variable to the squared power equals the other variable to the squared power.
Like, If you add a^2 and b^2 , you get c^2. The same thing happens with the equation of the circle, hence why it is x^2+y^2=r^2.

6:53 PM
Anonymous said...

the equation of a circle and the pythagorean theorem are similar by the facts that there are 3 variables, all 3 variables are being squared, and 2 of the squared variables are the sum of the other variable aquared.

8:36 PM
Anonymous said...

the equation of a circle is similar to the pythagoren theorem because in both, the added variables are squared as well as the sum of the variables. the equation of a circle is x^2+ y^2= r^2. the pythagorean theorum is a^2+b^2=c^2.

10:19 PM
Anonymous said...

The equation of a circle is similar to Pythagorean's Theorem because Pythagorean's Theorem is A^2 + B^2 = C^2, where x^2 + y^2 = r^2 is the equation for a circle. If you assume that x y and r are a b and c respectively, then the two equations are similar. Also, the equations are two terms added to make one whole. If you also assume that x = y, which must be true in a circle, and A = B and x = A, y = B, then the length r^2 must be equal to the length C^2.

11:57 PM
Anonymous said...

In the Pythagorean Theorem the equation is a^2 +b^2=c^2 and for a circle its x^2+y^2=r^2 they have the exact same concept but different variables. In both equations to find 'r' and 'c' you'd have to add 'a^2' and 'b^2' and square root the answer to get 'c' and you'd use the same concept for the circle equation. To find 'a' or 'b' ,you'd have to subtract the given squared value with the squared value of 'c'. You'd do the same thing to find 'x' or 'y' in the equation of a circle.

3:48 PM

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